Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
pallavi pradeep bhardwaj Grade: 12

The initial temperature of a body is 80 degree celcius If its temperature falls to 64 degree celcius in 5 min and in 10 min to 52 degree celcius then the temperature of surrounding will be

7 years ago

## Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points

Dear pallavi

assume newtons law of cooling

dT/dt =-k(T-To)  ...................1

To is the temperature of sorrunding

dT = 64-80 =-16

so dT/dt  =-16/5  oC /min

mean temperature T = (80 + 64)/2 = 72

so put these value in equation 1

-16/5 = -k(72 -To)   ....................a

for the next 5 sec

mean temperature T = (64 + 52)/2 =58

and dT/dt = (52-64)/5 = -12/5

so put again in equation  1

-12/5  = -k( 58 - To) ............b

now  divide equation a by b

16/12   = (72-To) /(58-To)

To =16

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed
solution very  quickly.
We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

All the best.

Regards,
Askiitians Experts
Badiuddin

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Thermal Physics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details

## Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details