MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
pallavi pradeep bhardwaj Grade: 12
        

The initial temperature of a body is 80 degree celcius If its temperature falls to 64 degree celcius in 5 min and in 10 min to 52 degree celcius then the temperature of surrounding will be

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear pallavi


assume newtons law of cooling


dT/dt =-k(T-To)  ...................1


To is the temperature of sorrunding


dT = 64-80 =-16   


so dT/dt  =-16/5  oC /min


mean temperature T = (80 + 64)/2 = 72


so put these value in equation 1


-16/5 = -k(72 -To)   ....................a


for the next 5 sec


mean temperature T = (64 + 52)/2 =58


and dT/dt = (52-64)/5 = -12/5


so put again in equation  1


-12/5  = -k( 58 - To) ............b


now  divide equation a by b


 16/12   = (72-To) /(58-To)


To =16


Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed
solution very  quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin


 


 

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
Get extra Rs. 2,756 off
USE CODE: AR07
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details
Get extra Rs. 2,968 off
USE CODE: AR07

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details