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```				   The initial temperature of a body is 80 degree celcius If its temperature falls to 64 degree celcius in 5 min and in 10 min to 52 degree celcius then the temperature of surrounding will be
```

6 years ago

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### Answers : (1)

```										Dear pallavi
assume newtons law of cooling
dT/dt =-k(T-To)  ...................1
To is the temperature of sorrunding
dT = 64-80 =-16
so dT/dt  =-16/5  oC /min
mean temperature T = (80 + 64)/2 = 72
so put these value in equation 1
-16/5 = -k(72 -To)   ....................a
for the next 5 sec
mean temperature T = (64 + 52)/2 =58
and dT/dt = (52-64)/5 = -12/5
so put again in equation  1
-12/5  = -k( 58 - To) ............b
now  divide equation a by b
16/12   = (72-To) /(58-To)
To =16
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very  quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin

```
6 years ago

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