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Anand Rananaware Grade: 11
        


Log2 y = log4(xy-2), log9 x2 +log3 (x-y) = 1


Find x & y


6 years ago

Answers : (2)

SAGAR SINGH - IIT DELHI
879 Points
										

Dear student,


It is


logy=1/2log(xy-2)


y=(xy-2)^1/2


y2=xy-2


Similaryly get an equation from the 2nd one...


solve the two to find x and y


 

6 years ago
Neer Varshney
76 Points
										

Log2Y=log4(xy-2)


log2Y=log22(xy-2)


log2y=(1/2)*log2(xy-2)


2log2y=log2(xy-2)


log2y2= log2(xy-2)


log2y2 - log2(xy-2) = 0


log2y2 - log2(xy-2) = log21


log2(y2/xy-2)= log21


y2/xy-2 = 1


y2 = xy-2 ......(1).


Similarly for log9x2 + log3(x-y) = 1


 log32x2 + log3(x-y) = log33.


2/2log3x + log3(x-y) = log33


log3x+log3(x-y) = log33


log3(x*(x-y))= log33


x(x-y) = 1 ..............(2).


Now solve equations (1)&(2) and you will get the answer. 


if you are satisfied with the solution than approve.

6 years ago
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