X gm of a certain oxide of nitrogen was slowly passed over heated copper to yield CuO and N2 gas. The increase in the weight of copper was 5.33 gm 4 litre of N2 gas at 140C and 754 mm of Hg was also obtained. What is the formula of the oxide.

Question

Sunil Kumar FP · Answer

we have ,
let the formula of the compound be NaOb,
we have to find the formula of the compound.
NaOb +2bCu --------a/2 N2 +bCu2O
mole of N2 formed from ideal gas equation=PV/RT P=754/760=.99 atm V=4lt n= to calculate T=413 K n=.99*4/(.0821*413)
n=.117 mole Thus,a/2=.117,a=.234 difference in weight=143b-63.5*2b=5.33 b=.33 b/a=3/2 Thus the formula is N2O3

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X gm of a certain oxide of nitrogen was slowly passed over heated copper to yield CuO and N2 gas. The increase in the weight of copper was 5.33 gm 4 litre of N2 gas at 140C and 754 mm of Hg was also obtained. What is the formula of the oxide.

X gm of a certain oxide of nitrogen was slowly passed over heated copper to yield CuO and N2 gas. The increase in the weight of copper was 5.33 gm 4 litre of N2 gas at 140C and 754 mm of Hg was also obtained. What is the formula of the oxide.

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X gm of a certain oxide of nitrogen was slowly passed over heated copper to yield CuO and N2 gas. The increase in the weight of copper was 5.33 gm 4 litre of N2 gas at 140C and 754 mm of Hg was also obtained. What is the formula of the oxide.

X gm of a certain oxide of nitrogen was slowly passed over heated copper to yield CuO and N2 gas. The increase in the weight of copper was 5.33 gm 4 litre of N2 gas at 140C and 754 mm of Hg was also obtained. What is the formula of the oxide.

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