When one mole of non-volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is?

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Prashik Gaikwad · Answer

Since Relative lowering vapour pressure is equal to mole fraction of solute i.e., P°/P°1=X2=n2/n1+n2=1/1+3=1/4=0.25 mm HgTherefore Relative lowering vapour pressure of pure solvent in solution is 0.25 mm Hg

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When one mole of non-volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is?

When one mole of non-volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is?

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When one mole of non-volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is?

When one mole of non-volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is?

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