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Simran Bhatia Grade: 11
        To a 25 mL H2O2 solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 20 mL of 0.3 N sodium thiosulphate solution. Calculate the volume strength of H2O2 solution.
3 years ago

Answers : (1)

Kevin Nash
askIITians Faculty
332 Points
										Sol. Meq of H2O2 = Meq of Na2S2O3

If N is normality of H2O2, then
N × 25 = 0.3 × 20
⇒ N = 0.24
⇒ Volume strength = N × 5.6 = 1.334 V
3 years ago
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