0

Guest

Courses New

The velocity of electron in third ecicted state of be+3 will be

The velocity of electron in third ecicted state of be+3 will be

Grade:11

1 Answers

Priyanshu kumar
27 Points
6 years ago
We know that, velocity of an electron in any Bohr orbit is V=Vo ×Z/n , where z= atomic no. of element and n= no. of Bohr orbit and Vo =2.16×10^6 ms^-1So in this case , z=4 (Beryllium) and n=4(3rd excited state).So, putting all values, V=2.16×10^6 × 4/4 = 2.16×10^6 ms^-1

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More