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The vapour pressure of benzene atis lowered by 10 mm by dissolving 2 g of a non–volatile substance in 78 g of benzene. The vapour pressure of pure benzene atis 750 mm. The molecular mass of the substance will be:

The vapour pressure of benzene atis lowered by 10 mm by dissolving 2 g of a non–volatile substance in 78 g of benzene. The vapour pressure of pure benzene atis 750 mm. The molecular mass of the substance will be:

Grade:12

1 Answers

Rituraj Tiwari
askIITians Faculty 1792 Points
3 years ago
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