The value of delta H for the reaction below is -790kJ. The enthalpy change accompanying the reaction of 0.95 g of S is___kJ.2S (s) + 3O2 (g) ¬ 2SO3 (g)

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Rituraj Tiwari · Answer

dear student, value of H= .95*(1 mol of S/32 g)*(-790kj/2mol S) = -12kj thank you

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The value of delta H for the reaction below is -790kJ. The enthalpy change accompanying the reaction of 0.95 g of S is___kJ.2S (s) + 3O2 (g) ¬ 2SO3 (g)

The value of delta H for the reaction below is -790kJ. The enthalpy change accompanying the reaction of 0.95 g of S is___kJ.2S (s) + 3O2 (g) ¬ 2SO3 (g)

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The value of delta H for the reaction below is -790kJ. The enthalpy change accompanying the reaction of 0.95 g of S is___kJ.2S (s) + 3O2 (g) ¬ 2SO3 (g)

The value of delta H for the reaction below is -790kJ. The enthalpy change accompanying the reaction of 0.95 g of S is___kJ.2S (s) + 3O2 (g) ¬ 2SO3 (g)

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