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Radhika Batra Grade: 11
        The energy of an electron in the first Bohr orbit of H-atom is -13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)  

a. -3.4 eV
b. -4.2 eV
c. -6.8 eV
d. +6.8 eV
3 years ago

Answers : (1)

Kevin Nash
askIITians Faculty
332 Points
										The energy of an electron in a Bohr atom is expressed as where, k = constant,

Z = atomic number,
N = orbit number
E_n = - 〖kZ〗^2/n^2
= - 13.6 eV for H (n = 1)
When n = 2,
E2 = E_2 = (- 13.6)/2^2 eV
= - 3.40 eV
(n can have only integral value 1, 2, 3,……. ∞)
3 years ago
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