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The energy of an electron in the first Bohr orbit of H-atom is -13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are) a. -3.4 eV b. -4.2 eV c. -6.8 eV d. +6.8 eV

The energy of an electron in the first Bohr orbit of H-atom is -13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)
a. -3.4 eV
b. -4.2 eV
c. -6.8 eV
d. +6.8 eV

Grade:11

1 Answers

Kevin Nash
askIITians Faculty 332 Points
9 years ago
The energy of an electron in a Bohr atom is expressed as where, k = constant, Z = atomic number, N = orbit number E_n = - 〖kZ〗^2/n^2 = - 13.6 eV for H (n = 1) When n = 2, E2 = E_2 = (- 13.6)/2^2 eV = - 3.40 eV (n can have only integral value 1, 2, 3,……. ∞)

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