0

Guest

Courses New

The difference between deltaH and DELTAE for the reaction 2C6H6 (l) +15O2 - 12CO2 (g) + 6H2O (l) at 25*C in KJ is

The difference between deltaH and DELTAE for the reaction 2C6H6 (l) +15O2 - 12CO2 (g) + 6H2O (l) at 25*C in KJ is

Question Image
Grade:12th pass

1 Answers

Rituraj Tiwari
askIITians Faculty 1792 Points
3 years ago
Heat of reaction at constant pressure is ΔH and at constant volume is ΔU.

ΔH-ΔU=ΔngRT

The difference between heats of reaction at constant pressure and constant volume for the following reaction at 25 C in kJ.

2C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(l)

ΔH-ΔU=ΔngRT

Δng=12-15=-3

ΔngRT=(-3)*(8.314*10-3KJ/mol/K)*(298 K)=-7.43

Hence ΔH-ΔU = -7.4KJ/mole

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More