MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Radhika Batra Grade: 11
        The average velocity of an ideal gas molecule at 27°C is 0.3 m/s. The average velocity at 927°C will be 

a. 0.6 m/s
b. 0.3 m/s
c. 0.9 m/s
d. 3.0 m/s
3 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
										Sol. Expression for average velocity is uavg = √(8RT/πM)

For the same gas but at different temperature
(u_avg 〖(T〗_1) )/(u_avg (T_2 ) ) = √(T_1/T_2 ) = √(300/1200) = 1/2
⇒ uavg (927°C) = 2 × uavg (27°C) = 0.6 ms-1
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
Get extra Rs. 2,385 off
USE CODE: COUPON10
Get extra Rs. 413 off
USE CODE: COUPON10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details