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Question in image (Q31)

Question in image (Q31)

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Grade:12

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
9 years ago
LET the final concentration of both the reaction be k
initial conc of A=4x
initial concentration of b=x
for A t=(2.303*5*log4x/k)/.693
for B t=(2.303*15*logx/k)/.693
on solving 1 and 2 we get log(x/k)=log2
t=2.303*15*log2/.693=15 min

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