On dissolving 10.8 g glucose in 240 gm of water its boiling point increases by 0.13*C. Calculate the molicular elevation constant of water.Given mol. Mass of glucose=180.

Question

Vikas TU · Answer

From delta Tf = i*Kf*m 0.13 = 1*Kf*(10.8/180)/(240/1000) => Kf = 0.13/0.25 => 0.0052 This would be the constant.

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On dissolving 10.8 g glucose in 240 gm of water its boiling point increases by 0.13*C. Calculate the molicular elevation constant of water.Given mol. Mass of glucose=180.

On dissolving 10.8 g glucose in 240 gm of water its boiling point increases by 0.13*C. Calculate the molicular elevation constant of water.Given mol. Mass of glucose=180.

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On dissolving 10.8 g glucose in 240 gm of water its boiling point increases by 0.13*C. Calculate the molicular elevation constant of water.Given mol. Mass of glucose=180.

On dissolving 10.8 g glucose in 240 gm of water its boiling point increases by 0.13*C. Calculate the molicular elevation constant of water.Given mol. Mass of glucose=180.

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