if you are given avagadro number’s of atom’s of a gas ‘x’ at half of the atom are converted into x ( g)+ energy by energy the delta H . the IE IS 1) 2deltaH/ N a 2) 2 N a /delta H 3)delta H/ 2 Na 4) Na / delta H

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Sakshi · Answer

hey student..
for this question you just need to use the basic definations of ionization enthalpy
The ionization energy (IE) is qualitatively defined as the amount of energy required to remove the most loosely bound electron, the valence electron, of an isolated gaseous atom to form a cation.

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if you are given avagadro number’s of atom’s of a gas ‘x’ at half of the atom are converted into x ( g)+ energy by energy the delta H . the IE IS 1) 2deltaH/ N a 2) 2 N a /delta H 3)delta H/ 2 Na 4) Na / delta H

if you are given avagadro number’s of atom’s of a gas ‘x’ at half of the atom are converted into x₍_{g)+ energy by energy the delta H . the IE IS}
_{1) 2deltaH/ N}_{a 2) 2}_N_a_{/delta H}

3)delta H/₂_{Na 4) Na /}_{delta H}

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if you are given avagadro number’s of atom’s of a gas ‘x’ at half of the atom are converted into x ( g)+ energy by energy the delta H . the IE IS 1) 2deltaH/ N a 2) 2 N a /delta H 3)delta H/ 2 Na 4) Na / delta H

if you are given avagadro number’s of atom’s of a gas ‘x’ at half of the atom are converted into x(g)+ energy by energy the delta H . the IE IS1) 2deltaH/ Na 2) 2Na /delta H 3)delta H/ 2Na 4) Na /delta H

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if you are given avagadro number’s of atom’s of a gas ‘x’ at half of the atom are converted into x₍_{g)+ energy by energy the delta H . the IE IS}
_{1) 2deltaH/ N}_{a 2) 2}_N_a_{/delta H}

3)delta H/₂_{Na 4) Na /}_{delta H}