how to find the equivalent weight of K4[Fe(CN)6] in the reaction K4[Fe(CN)6]---(K^+ ) + (Fe^+3) +CO2+(NO3^-1).If the molar mass of K4[Fe(CN)6] is M

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how to find the equivalent weight of K4[Fe(CN)6] in the reaction K4[Fe(CN)6]--->(K^+ ) + (Fe^+3) +CO2+(NO3^-1).If the molar mass of K4[Fe(CN)6] is M

Vikas TU · Answer

U need to find the valence factor first for the Fe in K4[Fe(CN)6] . Oxidation state of Fe is => +2 Valence factor = 3 – 2 = 1 Eq. Weight = M/1 = M

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how to find the equivalent weight of K4[Fe(CN)6] in the reaction K4[Fe(CN)6]--->(K^+ ) + (Fe^+3) +CO2+(NO3^-1).If the molar mass of K4[Fe(CN)6] is M

how to find the equivalent weight of K4[Fe(CN)6] in the reaction
K4[Fe(CN)6]--->(K^+ ) + (Fe^+3) +CO2+(NO3^-1).If the molar mass of K4[Fe(CN)6] is M

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how to find the equivalent weight of K4[Fe(CN)6] in the reaction K4[Fe(CN)6]--->(K^+ ) + (Fe^+3) +CO2+(NO3^-1).If the molar mass of K4[Fe(CN)6] is M

how to find the equivalent weight of K4[Fe(CN)6] in the reactionK4[Fe(CN)6]--->(K^+ ) + (Fe^+3) +CO2+(NO3^-1).If the molar mass of K4[Fe(CN)6] is M

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how to find the equivalent weight of K4[Fe(CN)6] in the reaction
K4[Fe(CN)6]--->(K^+ ) + (Fe^+3) +CO2+(NO3^-1).If the molar mass of K4[Fe(CN)6] is M