For a reversible process at T=300k ,the volume increases from Vi=1L to Vf=10L .calculate del H(change in enthalpy) if the process is isothermal 1)11.47kj 2)4.98kj 3)0 4)-11.47kj

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Vikas TU · Answer

H = U + delta(PV) U is zero as the process is isothermal. Therefore, H = 0 that is the enthalpy would be zero as well for this process.

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For a reversible process at T=300k ,the volume increases from Vi=1L to Vf=10L .calculate del H(change in enthalpy) if the process is isothermal 1)11.47kj 2)4.98kj 3)0 4)-11.47kj

For a reversible process at T=300k ,the volume increases from Vi=1L to Vf=10L .calculate del H(change in enthalpy) if the process is isothermal
1)11.47kj
2)4.98kj
3)0
4)-11.47kj

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For a reversible process at T=300k ,the volume increases from Vi=1L to Vf=10L .calculate del H(change in enthalpy) if the process is isothermal 1)11.47kj 2)4.98kj 3)0 4)-11.47kj

For a reversible process at T=300k ,the volume increases from Vi=1L to Vf=10L .calculate del H(change in enthalpy) if the process is isothermal1)11.47kj2)4.98kj3)04)-11.47kj

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For a reversible process at T=300k ,the volume increases from Vi=1L to Vf=10L .calculate del H(change in enthalpy) if the process is isothermal
1)11.47kj
2)4.98kj
3)0
4)-11.47kj