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AIPMT 2011 Q58 Please provide a detailed solution.......

AIPMT 2011 Q58 Please provide a detailed solution.......

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Grade:12th pass

1 Answers

Bhavya
askIITians Faculty 1281 Points
7 years ago
Cu2+ + e -----> Cu+ (1)
Cu++ e -------> Cu (2)
Now, we want the equation as:-
Cu2+ + 2e -----> Cu (3)
which can be gained by adding 1 and 2
\DeltaG1 +\DeltaG2 =\DeltaG3
-nFE1 – nFE2 = -nFE3
Dividing both sides by F and putting desired values we get:-
-1*0.15 -1*0.5 = -2*E3
-0.65/-2 = 0.325 V = E3

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