A cylinder of cooking gas supplied by Indian Oil Corporation is assumed to contain 14 kg of butane (ΔHc for C4H10 = - 2600 kJ mol-1). If a small family of three persons, requires 10,000 J of heat energy per day for cooking, the gas in the cylinder would last for

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Ashish bedi · Answer

14kg butane =241.3 molesTotal energy released =241.3*2600*1000 joules. Days gas last = 241.3*2600*1000/1000 0= 62738 days

Deep Mukherjee · Answer

63 days = 62.7 = 627380/10000 Days gas last = 627380. = 241.3*2600KJ Total energy released = 241.3 moles 14kg butane =

Deep Mukherjee · Answer

14kg butane = 241.3 moles. Total energy released = 241.3*2600KJ = 627380. Days gas last = 627380/10000=62.7 = 63 days.

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A cylinder of cooking gas supplied by Indian Oil Corporation is assumed to contain 14 kg of butane (ΔHc for C4H10 = - 2600 kJ mol-1). If a small family of three persons, requires 10,000 J of heat energy per day for cooking, the gas in the cylinder would last for

A cylinder of cooking gas supplied by Indian Oil Corporation is assumed to contain 14 kg of butane (ΔHc for C4H10 = - 2600 kJ mol-1). If a small family of three persons, requires 10,000 J of heat energy per day for cooking, the gas in the cylinder would last for

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A cylinder of cooking gas supplied by Indian Oil Corporation is assumed to contain 14 kg of butane (ΔHc for C4H10 = - 2600 kJ mol-1). If a small family of three persons, requires 10,000 J of heat energy per day for cooking, the gas in the cylinder would last for

A cylinder of cooking gas supplied by Indian Oil Corporation is assumed to contain 14 kg of butane (ΔHc for C4H10 = - 2600 kJ mol-1). If a small family of three persons, requires 10,000 J of heat energy per day for cooking, the gas in the cylinder would last for

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