20 g of impure NaCl solution is added to aqueous solution having excess AgNO3. AgCl precipitation is obtained with mass 28.7g. find % purity of NaCl.

Question

abhishek kumar · Answer

i think it should be 20 percent

vindhya · Answer

how, can you please tell me.

akash · Answer

as 0.2 moles of agcl is produced it means Chlorine obtained from nacl was also 0.2 moles. this implies 0.2 moles of nacl were present in the impure solution. molesXatomic weight(nacl)= MASS of NaCl present in impure substance.

vindhya · Answer

ya thanks, but the answer i have is 58.8%. so if anyone can provide a reason for this answer, i'll be really thankful. still thank you Mr. Akash

akash · Answer

my ans is 58.5. a little error in decimal places does not matters much as in exam options are not kept that close. so 58.5 is correct.

vindhya · Answer

thanks a lot. your answer is approved

abhishek kumar · Answer

sory corect answer is 58.5 you can approach it by writting the balance chemical eqn {1 mol agcl will be produced by one mol of nacl} so 28.7g of agcl ie;0.2 mol will be produced by 0.2 mol of nacl now 0.2 mol nacl is equal to 11.7 gm of nacl . hence % purity =(11.7/20)*100=58.5%

vindhya · Answer

thanks Mr. abhishek kumar

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20 g of impure NaCl solution is added to aqueous solution having excess AgNO3. AgCl precipitation is obtained with mass 28.7g. find % purity of NaCl.

20 g of impure NaCl solution is added to aqueous solution having excess AgNO3. AgCl precipitation is obtained with mass 28.7g. find % purity of NaCl.

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20 g of impure NaCl solution is added to aqueous solution having excess AgNO3. AgCl precipitation is obtained with mass 28.7g. find % purity of NaCl.

20 g of impure NaCl solution is added to aqueous solution having excess AgNO3. AgCl precipitation is obtained with mass 28.7g. find % purity of NaCl.

8 Answers

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