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`        Calculate the amount of 92U235 which must go nuclear fission to produce the same amount of energy as produced by 1 ton of coal.  The heat of combustion of coal is 8X103 cal/gram.  The fission of 92U235 produces 200 Mev energy/fission.  (Use 1 cal = 4.2 J, 1 ton = 106gram.  AV number is 6.023X1023 and 1. 602 X 10-19.  J= 1eV)`
8 years ago

10 Points
```										Hi Kiran,
combustion of coal is 8X103 cal/gram
1 ton produces=8X103x106x4.2 J
200 MeV = 200 * 106*1. 602 * 10-19.  J/fission
let y fissions
then y*200 * 106x1. 602 X 10-19.=8X103x106x4.2
y=10.487*1020 atoms
no of moles = y/6.023X1023
=0.00174 moles
```
8 years ago
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