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A glass tube of volume 112ml,containing a gas is partially evacuated till the pressure in it drops to 3.8*10-5 torr at 00C.the number of molecules of the gas remaining in the tube is?
volume = 0.112 L
pressure = 3.75 atm
temp = 273K
gas law is PV=nRT
n=3.75*0.112/(0.0821*273)
n=0.01874 moles
A mole has 6.0221415×1023 atoms or molecules of the pure substance being measured
no. of molecules = 112.87x1020
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regards
Ramesh
HI sameer ali
V=112 ml
P = 3.8*10-5 torr
T=00C=273 k
Use the formula PV=nRT
here n number of mole
and R is gas constant
and find the value of n
and we know that 1 mole of gas contain 1 avagadro number(A) of molecules
so n mole of contain n*A number of molecule at 00C
Take care of units during calculation
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