Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

Get extra R 650 off


a weak acid has dissociation constant 10-5

what is its equilibrium cinstant with strong base?

7 years ago


Answers : (1)


There exists a relationship between the value of Ka for an acid HA and the value of Kb for its conjugate base A. Since adding the ionization reaction for HA and the ionization reaction of A always gives the reaction for the self-ionization of water, the product of the acidity and basicity constants gives the dissociation constant of water (Kw), which is 1.0 × 10-14 M2 at 25°C. In other words,

Ka*Kb = Kw

kb = 10-14 / 10-5

    = 10-9




7 years ago

Post Your Answer

Other Related Questions on Physical Chemistry

how to balance following redox reaction in basic medium. C 4 H 4 O 6 2- +ClO 3 - =CO 3 2- +Cl - Please, balance with complete steps.
Balance C 4 H 4 O 6 2- + ClO 3 1- = 4CO 3 2- + Cl 1- C 4 = +6 Cl = +5 4C = +16 Cl = -1 Hence from the above calculation of oxidation no. C shows oxidation by 10 and Cl undergoes reduction...
Prachi 8 days ago
3C 4 H 4 O 6 2- + 5ClO 3 1- + 18OH - = 12CO 3 2- + 5Cl - [ H = 30, O = 51] [ H = 0, O = 36] Due to deficiency of hydrogen and oxygen on right side we add 15H 2 O on the right side Final...
Prachi 8 days ago
IN an experiment 500 ml of 0.01 M of kmno4 solution is added to 500 ml of KI solution in basic medium.The resultant solution was titrated with 0.015 M na2s2o3 solution using starch...
On reaction. KmnO4 will reduce to MnO2 and KI to I2. moles of Mn x v.f = moles of I2 x v.f 0.01*500 x 3 = mmoles x 1 millimoles = 15 mm. after then, the titration with Na2S2O3 , Na2S2O3 +...
Vikas TU 2 months ago
i am not getting the correct sorry i am really sorry my question was wrong ki has 0.1 M THEN HOW ARE WE SUPPOSED TO DO IT NOW
Iswarya Mahati 2 months ago
The molar volumes of ice and water are 0.0196 and 0.0190 litres per mole at 273K. If ΔHefor the transition of ice to water is 1440 calories per mole at 1 atm pressure, find ΔU.
Since heat is absorbed here at constant pressure so ΔH = 1440 calories ΔU can be calculated by using the formula : ΔU=ΔH-PΔV P= 1atm, ΔV = 0.0196L - 0.180L = 0.0016 L PΔV = 1*0.0016=...
navneet 29 days ago
why p mitrophenol is major product than o nitrophenol ?
@ yogesh in the case of para nitrophenol , the interaction between the molecules are stronger due to intermolecular hydrogen bonding . and results in more stability and majority also . on...
Umakant biswal one month ago
base CH 3 -CHO+HCHO​----------------> answer this rextion
Dear student In the presence of base, it will undergo aldol condensation as one of the reactant is having -H.If HCHO is given in excess then the reaction will proceed in the given way...
Bhavya one month ago
why carboxylic acid remove carbon di oxide from sodium bicarbonate but phenol does not?
phenol is acidic in nature , but not that muchj acidic to react with nahco3 . phenol are weakly acidic in nature . they turn blue litmus red and react with alkali metals and alkalies to...
Umakant biswal one month ago
Phenol is a very weak acid as compared to carboxylic acid and it cannot react with a weak base like sodium bicarbonate
Amay chugh one month ago
View all Questions »

  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 3,750 off

Get extra R 650 off

More Questions On Physical Chemistry

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details