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is the answer 4.6?
at a constant temperature P is infersely proportionsl to 1/V
PV=comstant
at same temperature apply P1V1 = P2V2
thus u will get P as 1.15 bar
P1V1=P2V2.92*.6= .12*P2
P2= 4.6 bar :answer
Hi Tejas,
V1=0.6 lit
V2=V1-V1*20/100
= V1(1-20/100)=V1(80/100)
P1=0.92 bar
Boyle's law: P1*V1=P2*V2
0.92*V1=P2*V1*0.8
P2=0.92/0.8=1.15 bar
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