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```				   a gas occupies 0.6 litres under a pressure of 0.92 bar. under what pressure will the volume of gas be reduced by 20% of its original volume ? ( temp is constant)
```

7 years ago

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```										is the answer 4.6?
```
7 years ago
```										at a constant temperature   P is infersely  proportionsl  to   1/V
PV=comstant
at same temperature apply P1V1 = P2V2
thus u will get P as 1.15 bar
```
7 years ago
```										P1V1=P2V2.92*.6= .12*P2
```
7 years ago
```										Hi Tejas,
V1=0.6 lit
V2=V1-V1*20/100
= V1(1-20/100)=V1(80/100)
P1=0.92 bar
Boyle's law: P1*V1=P2*V2
0.92*V1=P2*V1*0.8
P2=0.92/0.8=1.15 bar
```
7 years ago

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