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tejas ramkumar Grade: 11
        a gas occupies 0.6 litres under a pressure of 0.92 bar. under what pressure will the volume of gas be reduced by 20% of its original volume ? ( temp is constant)
7 years ago

Answers : (4)

Naveen Gunturu
18 Points
										

is the answer 4.6?

7 years ago
anurag singhal
4 Points
										

at a constant temperature   P is infersely  proportionsl  to   1/V


PV=comstant


at same temperature apply P1V1 = P2V2


thus u will get P as 1.15 bar

7 years ago
trishit thakur
4 Points
										

P1V1=P2V2
.92*.6= .12*P2


P2= 4.6 bar :answer

7 years ago
askiitian.expert- chandra sekhar
10 Points
										

Hi Tejas,


V1=0.6 lit


V2=V1-V1*20/100


    = V1(1-20/100)=V1(80/100)


P1=0.92 bar


Boyle's law: P1*V1=P2*V2


                 0.92*V1=P2*V1*0.8


                  P2=0.92/0.8=1.15 bar

7 years ago
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