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				   The KE of an electron emitted from tunsten surface is 3.06 eV. What voltae would be required to bring an electron to rest?

7 years ago


Answers : (1)


KE of electron emitted frm tungsten surface is 3.06*1.602*10-19 J = 4.902*10-19

Let electron has been accelerated from rest through a potential difference of  V

  KE = qV = 1.6*10-19 *V = 4.902*10-19

         = 3.064 Volts


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IIT Kgp - 2005 batch

7 years ago

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