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Vishrant Vasavada Grade: 11
        The dissociation energy of H2 is 430.53 KJ/mol. If H2 is exposed to radiant energy of wavelength 253.7 nm, what % of radiant energy will be converted into KE?
7 years ago

Answers : (1)

Ramesh V
70 Points
										

The bond dissociation energy for the H-H bond is the energy required to break the H2 molecule (in its most stable geometry) into separate hydrogen atoms.


Radiant energy = 1242 eV-nm / 253.7 nm = 4.895 eV = 7.843x10-19 J


1 mole of electrons is 6.022 x 1023 electrons


so radiant energy = 472.28 KJ/mol


dissoc. energy     = 430.53 KJ/mol


KE = rad. enrgy - dissoc. energy


      = 472.28 - 430.53


      =41.75 KJ/mol


% of rad. enrgy to KE is = 41.75*100/472.28


                                           = 8.84 %


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Naga Ramesh

IIT Kgp - 2005 batch


     

7 years ago
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