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				   A metal was irradiated by light of frequency 3.2 X 10^15 s^-1. The photoelectron produced has its KR, 2 times the KE of photoelectron which was produced when the same metal was irradiated with a light of frequency 2.0 X 10^15 s^-1. What is its work function?

7 years ago


Answers : (1)


K.E = hv -W

w is work fucnction in ev

h is planks constant = 4.14x10-15 ev-sec

K.E1 = hv1 -W  and K.E2 = hv2 -W

(hv1 -W) = 2.(hv2 -W )

W = h(2v2 -  v1)

     = 4.14x10-15 * (4 - 3.2)*x1015

     Work function = 3.312 eV


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Naga Ramesh

IIT Kgp - 2005 batch

7 years ago

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