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M.vs vivek vardhan Grade: 12
        

The enthalpy of fusion of ice is 6kJ/mol. The heat capacity of water is 4.2j/g/K.What is the smallest amount of ice cubes at 0degrees,each containing i mole of water,that are needed to cool 500g of liquid water from 20 dgreess to 0degrees


Ans:7.Give me the complete solution

6 years ago

Answers : (1)

Pramod J AskiitiansExpert-IIT-B
36 Points
										

Dear student,


heat rejected by water = m*c*delT = 500*4.2*20


let m be the number of cubes


heat taken by cubes = m*6000


heat rejected = heat raken


=> m*6000 = 500*4.2*20


=> m = 7

6 years ago
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