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				   the angular momentum of an electron in 2s orbit is?


6 years ago

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										Dear Pankaj
$L = n{h \over 2\pi} = n\hbar$n=2L=h/∏
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AKASH GOYAL

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6 years ago
										angular momentum(mvr)=h/2pi(l(l+1))1/2
=h/2pi(0(0+1))1/2             {for 2s orbital l=0}
=0

6 years ago
										 according to bohr's theory ,angular momentam of electron is mvr =nh/2pi
angular momentam =nh/2pi
for 2s orbital value of principal quantam number (n) is 2
therefore angular momentam of electron is 2h/2pi= h/pi....

6 years ago

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