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the angular momentum of an electron in 2s orbit is?

6 years ago


Answers : (3)


Dear Pankaj

 L = n{h \over 2\pi} = n\hbar

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6 years ago

angular momentum(mvr)=h/2pi(l(l+1))1/2

                                    =h/2pi(0(0+1))1/2             {for 2s orbital l=0}


like my answer?

6 years ago

 according to bohr's theory ,angular momentam of electron is mvr =nh/2pi

          angular momentam =nh/2pi

  for 2s orbital value of principal quantam number (n) is 2

   therefore angular momentam of electron is 2h/2pi= h/pi....

6 years ago

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