MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
krishna yadav Grade: 12
        

The activation energies of two reactions are given as Ea1=40 J and Ea2= 80 J, then the relation between their rate constants can be written as:

6 years ago

Answers : (1)

AJIT AskiitiansExpert-IITD
68 Points
										

Dear krishna,


The arrhenius equation is K = A exp(-Ea/RT).  A is the pre - exponential factor and depends on reaction .


using this relatipon we can find easily ,


  K1/k2 =  (A1/A2) *exp((Ea2 - Ea1)/RT)  


putting values , we get ,   


K1/k2 =  (A1/A2) *exp(40/RT) 


Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation.


Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.



Win exciting gifts by answering the questions on Discussion Forum


6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 2,500 off
USE CODE: NANDA25
Get extra R 2,500 off
USE CODE: NANDA25

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details