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bharat singh Grade:
        

If initially the  concentration of A and B are both at equilibrium ,concentration of D will be twice of that of A , then what is the equilibrium constant of the reaction? the reaction is shown as below; A +B sign of  equilibrium C+D

6 years ago

Answers : (1)

Priyansh Goel
21 Points
										

Let there be a moles of A and B each at time =  0.


At equilibrium,


 


[A] =  a-x


[B] = a-x


[C] = x


[D] =  x


Keq =  x2/(a-x)2 ........................................  (1)


Given


[D]  = 2[A] so, x =  2(a-x)


Put this in (1)


Keq  = 4


If there is any error , plz do tell me.


 


If it is correct plz approve my answer.


 

6 years ago
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