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`        If initially the  concentration of A and B are both at equilibrium ,concentration of D will be twice of that of A , then what is the equilibrium constant of the reaction? the reaction is shown as below; A +B sign of  equilibrium C+D`
7 years ago

Priyansh Goel
21 Points
```										Let there be a moles of A and B each at time =  0.
At equilibrium,

[A] =  a-x
[B] = a-x
[C] = x
[D] =  x
Keq =  x2/(a-x)2 ........................................  (1)
Given
[D]  = 2[A] so, x =  2(a-x)
Put this in (1)
Keq  = 4
If there is any error , plz do tell me.

If it is correct plz approve my answer.

```
7 years ago
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