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dhawal kashyap Grade: 11
        









 when photons of energy 4.25ev strike at surface of a metal A, the ejected e- have maximum kinetic energy, Ta & de broglie wavelength lemda a  the  k max    of  e- emitted from other metal B by photons of energy 4.20ev is Tb = Ta - 1.50ev . If de broglie wavelength of these e- is lemda B = 2*lemda A  then which is not correct


A; work function of A is 2.25ev


B; work function of B is 3.70ev


C; Ta=2ev


D; Tb=2.75ev     


 
6 years ago
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