125 ml of 63% (w/v) H 2 C 2 O 4 .10H 2 O is made to react with 125 ml of 40% (w/v) NaOH Solution. Resullting sol is ( acidic/basic/neutral/alkaline/strongly acidic)

Question

125 ml of 63% (w/v) H 2 C 2 O 4 .10H 2 O is made to react with 125 ml of 40% (w/v) NaOH Solution. Resullting sol is ( acidic/basic/neutral/alkaline/strongly acidic)

Samkit Jain · Answer

Neutral as normally of both sol. Is same it can be calculated by normality =molarity *nfactor. Or by no of equivalent also we can find it that solution would be neutral

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125 ml of 63% (w/v) H 2 C 2 O 4 .10H 2 O is made to react with 125 ml of 40% (w/v) NaOH Solution. Resullting sol is ( acidic/basic/neutral/alkaline/strongly acidic)

125 ml of 63% (w/v) H₂C₂O₄.10H₂O is made to react with 125 ml of 40% (w/v) NaOH Solution. Resullting sol is ( acidic/basic/neutral/alkaline/strongly acidic)

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125 ml of 63% (w/v) H 2 C 2 O 4 .10H 2 O is made to react with 125 ml of 40% (w/v) NaOH Solution. Resullting sol is ( acidic/basic/neutral/alkaline/strongly acidic)

125 ml of 63% (w/v) H2C2O4.10H2O is made to react with 125 ml of 40% (w/v) NaOH Solution. Resullting sol is ( acidic/basic/neutral/alkaline/strongly acidic)

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125 ml of 63% (w/v) H₂C₂O₄.10H₂O is made to react with 125 ml of 40% (w/v) NaOH Solution. Resullting sol is ( acidic/basic/neutral/alkaline/strongly acidic)