When CH3CHO is treated with excess of HCHO in aqueous solution of Na2CO3 a product used in making explosives is obtained. Find the number of alcoholic group present in one molecule of the product.

Question

Vikas TU · Answer

the product formed is: When CH3CHO is treated with excess of HCHO in aqueous solution of Na2CO3 Pentaerythyritol tetranitrate. And the number of -OH groups are => four that is each from Nitrogen group as it has 4 nitro groups as substituents.

Dhruvin Kakadia · Answer

OH(-) is going to go through an acid base reaction with the alpha-H of Acetaldehyde, then CH2(-)-CH=O is formed which attacks on the carbonyl carbon of the formaldehyde. This will form OH-CH2-CH2-CH=O. Since, we have excess of HCHO, this reaction will take place 3 more times which in the end would give us the product, OH C----OH | | CH---C----C | | OH---C OH

Arunavo Debnath · Answer

CH3CHO+ HCHO REACT IN PRESENCE OF Na2CO3 AS ALDOL REACTION GIVE CHOCH2CH2OH. AS HCHO IS EXCESS CONTINUE ALDOL GIVE CHOC(CH2OH)3. AT LAST STAGE THIS PRODUCT AGAIN REACT WITH HCHO AS CNNIZARO REACTION GIVE OHCH2C(CH2OH)3 + HCOONa. Thus the primary alcohol gp in final product is 4.

Dhruv · Answer

Do three times aldol condensation and then cannizzaro rxn. You will get the answer. I am not able to upload image here. There's no option for this

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When CH3CHO is treated with excess of HCHO in aqueous solution of Na2CO3 a product used in making explosives is obtained. Find the number of alcoholic group present in one molecule of the product.

When CH3CHO is treated with excess of HCHO in aqueous solution of Na2CO3 a product used in making explosives is obtained. Find the number of alcoholic group present in one molecule of the product.

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When CH3CHO is treated with excess of HCHO in aqueous solution of Na2CO3 a product used in making explosives is obtained. Find the number of alcoholic group present in one molecule of the product.

When CH3CHO is treated with excess of HCHO in aqueous solution of Na2CO3 a product used in making explosives is obtained. Find the number of alcoholic group present in one molecule of the product.

4 Answers

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