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Plz solve the ques. Calculate the % of ionic character in NaF if electronegativities of Na and F are 0.9 and 4.0 respectively

Plz solve the ques. Calculate the % of ionic character in NaF if electronegativities of Na and F are 0.9 and 4.0 respectively

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Grade:11

1 Answers

Arun
25750 Points
6 years ago
Percentage ionic character in NaF
= [E.N.(Na) - E.N(F)]* 100/E.N.(Na)
= (4- 0.9) * 100/4
= 3.1 *25
= 77.5 %

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