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```        for m>0,n>0.show integration ---x(pow)m (1-x)(Pow)n from 0 to 1=
m!n!/(m+n+1)!```
7 years ago

147 Points
```										Dear yashika
for m>0,n>0
Im,n=∫xm(1-x)n dx  limit 0 to 1
intigrate by using 1st and 2nd function
=-1/(n+1)  xm(1-x)n+1  limit 0 to 1  +m/(n+1) ∫xm-1(1-x)n+1 dx  limit 0 to 1
=0 +m/(n+1) ∫xm-1(1-x)(1-x)n dx  limit 0 to 1
= m/(n+1) [∫xm-1(1-x)n dx - ∫xm(1-x)ndx ]    limit 0 to 1
=m/(n+1) [Im-1,n  - Im,n   ]
simplify     Im,n   =   m/(m+n+1) Im-1,n
=m*(m-1)/(m+n+1)(m+n)  Im-2,n
repeat this process you will get desire result

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```
7 years ago
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