MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Amit Saxena Grade: upto college level
        The electric field at a point associated with a light wave is E = (100 V/m) sin [(3.0 × 10^15 s^-1)t] sin [(6.0 × 10^15 s^-1)t]. If this light falls on a metal surface having  work  function of 2.0 eV, what will be the maximum kinetic energy of the photoelectrons?
3 years ago

Answers : (1)

Jitender Pal
askIITians Faculty
365 Points
										Sol. E = 100 sin[(3 * 10^15 s^–1)t] sin [6 * 10^15 s^–1)t]

= 100 ½ [cos[(9 * 10^15 s^–1)t] – cos [3 * 10^15 s^–1)t]
The w are 9 * 10^15 and 3 * 10^15
for largest K.E.
f base max = w base max/2π = 9 * 10^15/2π
E - ∅ base 0 = K.E.
⇒ hf = ∅ base 0 = K.E.
⇒ 6.63 * 10^-34 *9 * 10^15/2π * 1.6 * 10^19 – 2 KE
⇒ KE = 3.938 ev = 3.93 ev.
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
Get extra Rs. 413 off
USE CODE: COUPON10
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details
Get extra Rs. 445 off
USE CODE: COUPON10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details