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Shane Macguire Grade: upto college level
`        The electric current in an X-ray tube (from the target to the filament) operating at 40 kV is 10 mA. Assume that on an average, 1% of the total kinetic energy of the electrons hitting the target are converted into X-rays. (a) What is the total power emitted as X-rays and (b) how much heat is produced in the target every second?`
3 years ago

Deepak Patra
474 Points
```										V = 40 KV, i = 10 mA
1% of T base KE (Total Kinetic Energy) = X ray
i = ne or n = 10^-2/1.6 * 10^19 = 0.625 * 10^17 no.of electrons.
KE of one electron = eV = 1.6 * 10^-19 * 40 * 10^3 = 6.4 * 10^15 J
T base KE = 0.625 * 6.4 * 10^17 * 10^-15 = 4 * 10^2 J.
a) Power emitted in X-ray = 4 – 10^2 * (-1/100) = 4w
b) Heat produced in target per second = 400 – 4 = 396 J.

```
3 years ago
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