A battery of emf 60V is connected across a parallel combination of a 8 ohm resistor and a thick wire of negligible resistance.If the current observed is 6A, what is the internal resistance of the battery?

Question

Physics Expert · Answer

Calculate the internal resistance of the battery. Hence, the internal resistance is 12 ohm.

shubham · Answer

Internal resistance I=E/R+r 6= 60/8+r 48+6r=60-48 6r=12 ohm r=2 ohm Hence, the internal resistance is 2 ohm.

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A battery of emf 60V is connected across a parallel combination of a 8 ohm resistor and a thick wire of negligible resistance.If the current observed is 6A, what is the internal resistance of the battery?

A battery of emf 60V is connected across a parallel combination of a 8 ohm resistor and a thick wire of negligible resistance.If the current observed is 6A, what is the internal resistance of the battery?

2 Answers

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A battery of emf 60V is connected across a parallel combination of a 8 ohm resistor and a thick wire of negligible resistance.If the current observed is 6A, what is the internal resistance of the battery?

A battery of emf 60V is connected across a parallel combination of a 8 ohm resistor and a thick wire of negligible resistance.If the current observed is 6A, what is the internal resistance of the battery?

2 Answers

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Other Related Questions on Modern Physics

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