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5 years ago

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### Answers : (2)

										Dear Rajan,
$K_{\mathrm{max}} = hf - \varphi$$\varphi = hf_0,$ here f0 is threshold frequencyso,         1.2 = hf - ψ and,     4.2 = 1.5hf - ψsolve for ψ

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Askiitians Expert
Anil Pannikar
IIT Bombay

5 years ago
										when frequency is f then max kinetic energy is 1.2ev
(KE) = hf  -@                       (@ is work function)
1.2  = hf - @ .......1
when frequency increased by 50% then new frequency is f+f/2 =3f/2 and
(KE)max = 3hf/2 - @
4.2 = 3hf/2 - @ ................2
from 1 & 2
@ = 4.8ev ans

5 years ago

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