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`        Two small bodies of masses 2.00 kg and 4.00 kg are kept at rest at a separation of 2.0 m. Where should a particle of mass 0.10 kg be placed to experience no net gravitational force from these bodies? The particle is placed at this point. What is the gravitational potential energy of the system of three particles with usual reference level?`
3 years ago

Deepak Patra
474 Points
```										Sol. Let 0.1 kg man is x m from 2kg mass and (2 – x) m from 4 kg mass.
∴ 2 * 0.1/x^2 = - 4 * 0.1/ (2 - x)^2
Or 0.2/x^2 = - 0.4/(2 - x)^2
Or 1/x^2 = 2/(2 - x)^2 or (2 - x)^2 = 2 x^2
Or 2 – x = √2 x or x(r base 2 + 1)^2 = 2
Or x = 2/2.414 = 0.83 m from 2kg mass.

```
3 years ago
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