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Please get my these two questions solved. If a graph of acceleration versus position is given, then how to find the equation of position with respect to time

Please get my these two questions solved. 
If a graph of acceleration versus position is given, then how to find the equation of position with respect to time
 

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Grade:11

2 Answers

Manas Shukla
102 Points
7 years ago
U dont need to draw any graph for those two questions.
We can see the maximum height of the object is at 3.5 secs.
Now we can see from given graph that we need to find h = h1 – h2
h1 = height of object at t=5secs
h2 = height of object at t= 6 secs
which can be written as h = (H - h2) – (H – h1) where H is the maximum height.
H-h1 = \frac{1}{2}gt^{2} = 5 x 1.5 x 1.5
H-h2 = 5 x 2.5 x 2.5
h = 5 (6.25 – 2.25) = 20m
 
Manas Shukla
102 Points
7 years ago
For second question
Displacement will be = \sqrt{20^{2} + 10^{2}}
Thus X = 10\sqrt{5} = 22.36 km
Let me know if u need any further help.

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