Kinetic energy of a block of mass 2 kg is given as kinetic energy = 16t^4 and the block is moving in a circular path of radius 8 m .then find the power generated by the applied force in t = 1/2 sec in watt.

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Himanshu · Answer

Since power=force×velocityAcc/q Ke=16t^4 i.e. mv^2=32t^4i.e. At t=1/2 mv^2=2And Force=mv^2/ri.e. F=2/8Since, mv^2 =2 =>v^2=1 (since m=2)so, v=1Now, power=force× velocity=>P=2/8×1=2/8 watt

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Kinetic energy of a block of mass 2 kg is given as kinetic energy = 16t^4 and the block is moving in a circular path of radius 8 m .then find the power generated by the applied force in t = 1/2 sec in watt.

Kinetic energy of a block of mass 2 kg is given as kinetic energy = 16t^4 and the block is moving in a circular path of radius 8 m .then find the power generated by the applied force in t = 1/2 sec in watt.

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Kinetic energy of a block of mass 2 kg is given as kinetic energy = 16t^4 and the block is moving in a circular path of radius 8 m .then find the power generated by the applied force in t = 1/2 sec in watt.

Kinetic energy of a block of mass 2 kg is given as kinetic energy = 16t^4 and the block is moving in a circular path of radius 8 m .then find the power generated by the applied force in t = 1/2 sec in watt.

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