Given that p+q+r=0. two of them are equal in magnitude. the magnitude of third vector is √2 times that of the other two. which are the angles between these two vectors? 90, 135, 135 45, 45, 135 30, 60, 90 45, 90, 135 plz answer fast..

Question

Given that p+q+r=0. two of them are equal in magnitude. the magnitude of third vector is √2 times that of the other two. which are the angles between these two vectors? 90, 135, 135 45, 45, 135 30, 60, 90 45, 90, 135 plz answer fast..

Mohsin syed · Answer

Given:P+Q+R=0 SO, P+Q=-R Given P=Q P²+p²+2p²Cos∆=-q² 2p²+2p²cos∆=(p√2)² 2p²Cos∆=2p²-2p² Cos∆=0 ∆= 90 degree= angle btw p & q Now btw p and R P² +(p √2)²+2(p)(p√2)cos ∆= -q² P²+ 2p² +2p²√2cos∆=p² 2p²√2cos∆=-2p² Cos∆= -2p²/2p²√2 Cos∆ =-1/√2 ∆= 135 degree Hence angles are 90,135 q35

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Given that p+q+r=0. two of them are equal in magnitude. the magnitude of third vector is √2 times that of the other two. which are the angles between these two vectors? 90, 135, 135 45, 45, 135 30, 60, 90 45, 90, 135 plz answer fast..

Given that p+q+r=0. two of them are equal in magnitude. the magnitude of third vector is √2 times that of the other two. which are the angles between these two vectors?
90, 135, 135
45, 45, 135
30, 60, 90
45, 90, 135
plz answer fast..

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Given that p+q+r=0. two of them are equal in magnitude. the magnitude of third vector is √2 times that of the other two. which are the angles between these two vectors? 90, 135, 135 45, 45, 135 30, 60, 90 45, 90, 135 plz answer fast..

Given that p+q+r=0. two of them are equal in magnitude. the magnitude of third vector is √2 times that of the other two. which are the angles between these two vectors?90, 135, 13545, 45, 13530, 60, 9045, 90, 135plz answer fast..

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Given that p+q+r=0. two of them are equal in magnitude. the magnitude of third vector is √2 times that of the other two. which are the angles between these two vectors?
90, 135, 135
45, 45, 135
30, 60, 90
45, 90, 135
plz answer fast..