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Simran Bhatia Grade: 11
        A river 400 m wide is flowing at a rate of 2.0 m/s. A boat is sailing at a velocity of 10 m/s with respect to the water, in a direction perpendicular to the river. (a) Find the time taken by the boat to reach the opposite bank. (b) How far from the point directly opposite to the starting point does the boat reach the opposite bank?
3 years ago

Answers : (3)

Aditi Chauhan
askIITians Faculty
396 Points
										Sol. a) Here the boat moves with the resultant velocity R. But the vertical component 10 m/s takes him to the opposite shore. 

Tan θ = 2/10 = 1/5
Velocity = 10 m/s
distance = 400 m
Time = 400/10 = 40 sec.
b) The boat will reach at point C.
In ∆ABC, tan θ = BC/AB = BC/400 = 1/5
⇒ BC = 400/5 = 80 m.
3 years ago
Parikshit
13 Points
										Sol. a) Here the boat moves with the resultant velocity R. But the vertical component 10 m/s takes him to the opposite shore. Tan θ = 2/10 = 1/5 Velocity = 10 m/s distance = 400 m Time = 400/10 = 40 sec. b) The boat will reach at point C. In ∆ABC, tan θ = BC/AB = BC/400 = 1/5 ⇒ BC = 400/5 = 80 m.
										
7 months ago
Maya
13 Points
										Time =displacement (in y -direction)             —————————————              Speed(in y direction)Time=.   400              ,——                10        =40 sNow,Distance(in x direction) =s×t                                           =2m/s×40s=80m
										
one month ago
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