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A ring of m 1kg.r=10cm rotate about an axis through the centre and perpendicular to the plane find its MI

A ring of m 1kg.r=10cm rotate about an axis through the centre and perpendicular to the plane find its MI

Grade:11

1 Answers

Arun
25750 Points
6 years ago
Dear Pranav
 
 
for moment of inertia of ring about an axis passing through it’s centre
we have,
MI of ring = mr2
                =1*(10*10-2)
                =0.1kgm2
 

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