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A plank P is placed on a solid cylinder S, which rolls on a horizontal surface. The two are of equal mass. There is no slipping at any of the surfaces in contact. The ratio of the kinetic energy of P to the kinetic energy of S is?

A plank P is placed on a solid cylinder S, which rolls on a horizontal surface. The two are of equal mass. There is no slipping at any of the surfaces in contact. The ratio of the kinetic energy of P to the kinetic energy of S is?

Grade:11

1 Answers

Nishant
13 Points
6 years ago
Kinetic energy of plank: 1/2 (m)((2v)^2)Kinetic energy of cylinder is 1/2 IW^2where W is angular velocitySo kinetic energy of cylinder is 3/4(mv^2)As angular velocity can be written as velocity/radius.Ke of plank is 2mv^2So the ratio becomes 8:3

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