a particle is projected with speed 4 √ 2 m/s at an angle 45 ° with horizontal . after some time t its radius of curvature of path becomes (25/8)m. the value of t

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Ashutosh · Answer

Radius= u^2 sin 2*Φ/g = (4√2)^2 sin 2*45/g = 32* sin90/g = 32*1/g25/8=32/gImplies that g=8*32/25T= 2u sinΦ/g = 2*4√2 sin45/g = 8√2 *1/√2 *1/g =8*25/(8*32) =25/32~0.7s

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a particle is projected with speed 4 √ 2 m/s at an angle 45 ° with horizontal . after some time t its radius of curvature of path becomes (25/8)m. the value of t

a particle is projected with speed 4 √2 m/s at an angle 45° with horizontal . after some time t its radius of curvature of path becomes (25/8)m. the value of t

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a particle is projected with speed 4 √ 2 m/s at an angle 45 ° with horizontal . after some time t its radius of curvature of path becomes (25/8)m. the value of t

a particle is projected with speed 4 √2 m/s at an angle 45° with horizontal . after some time t its radius of curvature of path becomes (25/8)m. the value of t

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