A particle is projected from the ground with an initial velocity of 20ms-1 at an angle of 300 with horizontal. The magnitude of change in velocity in 0.5 seconds is(g=10ms-1)

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Aditya · Answer

Resolve the velocity in x nd y componentsX component would be 10rt3 and y component wud be 10After 5 seconds x component would remain the same since there is no acceleration in that direction and y would be u-gt i.e 5 so resultant velocity will become (25+300)^½ so change in velocity is 20-rt(325)

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A particle is projected from the ground with an initial velocity of 20ms-1 at an angle of 300 with horizontal. The magnitude of change in velocity in 0.5 seconds is(g=10ms-1)

A particle is projected from the ground with an initial velocity of 20ms-1 at an angle of 300 with horizontal. The magnitude of change in velocity in 0.5 seconds is(g=10ms-1)

A particle is projected from the ground with an initial velocity of 20ms-1 at an angle of 300 with horizontal. The magnitude of change in velocity in 0.5 seconds is(g=10ms-1)

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A particle is projected from the ground with an initial velocity of 20ms-1 at an angle of 300 with horizontal. The magnitude of change in velocity in 0.5 seconds is(g=10ms-1)

A particle is projected from the ground with an initial velocity of 20ms-1 at an angle of 300 with horizontal. The magnitude of change in velocity in 0.5 seconds is(g=10ms-1)

A particle is projected from the ground with an initial velocity of 20ms-1 at an angle of 300 with horizontal. The magnitude of change in velocity in 0.5 seconds is(g=10ms-1)

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