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A particle is projected from the ground at an angle of theta with the horizontal at initial speed of u . Find the time after which velocity vector of the projectile is perpendicular to the initial velocity

A particle is projected from the ground at an angle of theta with the horizontal at initial speed of u . Find the time after which velocity vector of the projectile is perpendicular to the initial velocity

Grade:11

1 Answers

pothamsetty chethan
22 Points
6 years ago
Let the velocity be v at that given condition,V=ucosAi+(usinA-gt)j ,Initial velocity u=ucosAi+usinAj(WhereA is angle of projection)We know that ,when two vectors are perpendicular then their dot product is zeroV.u=0U^2cosA^2+u^2sinA^2-gtusinA=0U^2=ugtsinA(sinA^2+cosA^2=1)t=ucosecA/g

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