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A healthy young man standing at a distance of 7 m from a 11.8 m high building sees a kid slipping from the top floor. With what speed (assumed uniform) should he run to catch the kid at the arms height (1.8 m)?
3 years ago

Kevin Nash
332 Points
Sol. At point B (i.e. over 1.8 m from ground) the kid should be catched. For kid initial velocity u = 0

Acceleration = 9.8 m/s2
Distance S = 11.8 – 1.8 = 10 m
S = ut + ½ at2 ⇒ 10 = 0 + ½ (9.8) t2
⇒ t2 = 2.04 ⇒ t = 1.42.
In this time the man has to reach at the bottom of the building.
Velocity s/t = 7/1.42 = 4.9 m/s.
3 years ago
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